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EDEXCEL INTERNATIONAL A LEVEL MATHEMATICS • S3

THE INFERENCE CORE

Enter the deepest region of the statistical universe — where samples become evidence, estimators become signals, hypotheses are tested, relationships are measured, and uncertainty becomes inference.

STATISTICAL INFERENCE SYSTEM ONLINE
INFER
11
INFERENCE TOPICS
X̄
ESTIMATION SIGNAL
H₀
HYPOTHESIS CORE
χ²
DATA ASSOCIATION

TOPIC 01 • SAMPLING SYSTEM

Sampling

Sampling is the process of selecting observations from a population so that information about the population can be obtained without studying every member.

Population and Sample

The population is the complete set of individuals or objects being studied. A sample is a subset selected from that population.

Simple Random Sampling

In simple random sampling, every possible sample of the required size has an equal chance of being selected.

Using random numbers:

Members of a population can be numbered and random numbers can then be used to select the required sample.

Stratified Sampling

The population is divided into strata according to a relevant characteristic. A sample is then taken from each stratum, usually in proportion to the size of that stratum.

Sample from stratum = (stratum size / population size) × total sample size

Systematic Sampling

Individuals are selected at regular intervals from an ordered sampling frame, usually after choosing a suitable starting point.

Quota Sampling

The investigator sets quotas for different groups and continues selecting individuals until the required quotas are filled.

Comparing Sampling Methods

TOPIC 02 • DISTRIBUTION NETWORK

Combinations of Random Variables

S3 extends the Normal distribution to combinations of independent Normal random variables.

Linear Combinations

Suppose X and Y are independent Normal random variables:

X ~ N(μx, σx²)     Y ~ N(μy, σy²)

Then a linear combination of X and Y is also Normally distributed.

aX ± bY ~ N(aμx ± bμy, a²σx² + b²σy²)
Important:

Variances are added after multiplying them by the squares of the coefficients. The standard deviations themselves are not added.

WORKED EXAMPLE

X ~ N(20, 4²) and Y ~ N(15, 3²), independently. Find the distribution of 2X − Y.

Mean:

2(20) − 15 = 25

Variance:

2²(4²) + 1²(3²) = 64 + 9 = 73

Therefore:

2X − Y ~ N(25, 73)

TOPIC 03 • ESTIMATION ENGINE

Estimators and Standard Error

An estimator is a statistic used to estimate an unknown population parameter.

Estimator

The sample mean is commonly used as an estimator of the population mean μ.

X̄ = ΣX / n

Bias

An estimator is unbiased if its expected value is equal to the population parameter that it estimates.

E(X̄) = μ

Variance of the Sample Mean

For a random sample of n independent observations from a population with variance σ²:

Var(X̄) = σ² / n

Standard Error

SE(X̄) = σ / √n
Key idea:

Increasing the sample size reduces the standard error and therefore generally makes the sample mean a more precise estimator of μ.

Estimator of Population Variance

For a random sample, the usual unbiased estimator of the population variance uses n − 1 in the denominator.

S² = Σ(Xᵢ − X̄)² / (n − 1)

TOPIC 04 • CONFIDENCE FIELD

Confidence Intervals

A confidence interval provides a range of plausible values for an unknown population parameter.

Normal Mean with Known Variance

If the population is Normal with known variance σ², an interval estimate for μ can be constructed using the sampling distribution of X̄.

X̄ ± z × σ / √n

Here z is the appropriate percentage point of the standard Normal distribution for the required confidence level.

Interpreting a Confidence Interval

A confidence interval should be interpreted in terms of the method used to construct it. For example, a 95% confidence procedure produces intervals that contain the true parameter in approximately 95% of repeated samples.

Width of an Interval

A larger sample size gives a smaller standard error and therefore usually produces a narrower confidence interval.

TOPIC 05 • HYPOTHESIS ENGINE

Hypothesis Tests for a Normal Mean

Hypothesis testing provides a formal method for deciding whether sample evidence is inconsistent with a proposed population parameter.

Null and Alternative Hypotheses

Null hypothesis H₀:

The statement assumed to be true unless the sample provides sufficient evidence against it.

Alternative hypothesis H₁:

The competing statement supported when the null hypothesis is rejected.

Test Statistic

When the population variance is known, the sample mean can be standardised using:

Z = (X̄ − μ) / (σ / √n)

One-Tailed and Two-Tailed Tests

Significance Level

The significance level is the probability of rejecting H₀ when H₀ is actually true.

Conclusion

A statistical conclusion should be stated clearly in the context of the question.

Remember:

Do not say that H₀ has been proved true. A test either provides sufficient evidence to reject H₀ or does not provide sufficient evidence to reject H₀.

TOPIC 06 • CENTRAL LIMIT FIELD

Central Limit Theorem

The Central Limit Theorem allows the distribution of a sample mean to be approximated by a Normal distribution for sufficiently large samples, even when the underlying population is not Normal.

Sampling Distribution of the Mean

For a population with mean μ and variance σ², a sample mean based on n independent observations has:

E(X̄) = μ
Var(X̄) = σ² / n

For a Normal population, the sampling distribution of X̄ is exactly Normal. For a sufficiently large sample from a non-Normal population, the Central Limit Theorem provides a Normal approximation.

Standardising the Sample Mean

Z = (X̄ − μ) / (σ / √n)
Exam idea:

Always identify the population mean, population variance, sample size and required probability before standardising.

TOPIC 07 • COMPARISON MATRIX

Comparing Two Population Means

S3 also considers inference about the difference between two population means using independent samples.

Difference Between Sample Means

If two independent samples are taken from Normal populations with known variances:

E(X̄ − Ȳ) = μx − μy
Var(X̄ − Ȳ) = σx²/nx + σy²/ny

Standardising the Difference

Z = [(X̄ − Ȳ) − (μx − μy)] / √(σx²/nx + σy²/ny)

This can be used to construct confidence intervals or perform hypothesis tests about the difference between two population means.

Large samples:

Large-sample methods can also be used when population variances are unknown, using appropriate estimates of variability.

TOPIC 08 • RELATIONSHIP NETWORK

Spearman's Rank Correlation

Spearman's rank correlation coefficient measures the strength and direction of a monotonic relationship between two variables using their ranks.

Rank Differences

For each observation, calculate the difference d between its two ranks and then calculate d².

rₛ = 1 − [6Σd² / n(n² − 1)]

Interpreting rₛ

Ties

When tied values occur, appropriate ranks must be assigned before calculating the correlation coefficient.

Limitations

Correlation does not establish causation. Spearman's coefficient also describes association rather than proving that one variable causes changes in another.

TOPIC 09 • CORRELATION TEST NODE

Testing for Zero Correlation

A hypothesis test can be used to investigate whether there is evidence of a relationship between two variables.

Hypotheses

H₀: ρ = 0
H₁: ρ ≠ 0

Depending on the wording of the question, a one-tailed alternative may be appropriate.

Critical Values

For Spearman's rank correlation, critical values can be used to determine whether the observed rank correlation is sufficiently extreme to reject the null hypothesis.

Decision rule:

Compare the calculated statistic with the appropriate critical value for the chosen significance level and alternative hypothesis.

TOPIC 10 • CHI-SQUARED ANALYSIS

Goodness of Fit Tests

A chi-squared goodness-of-fit test can be used to investigate whether observed frequencies are consistent with a proposed probability model.

Observed and Expected Frequencies

The observed frequencies are the actual data. Expected frequencies are calculated from the model assumed under the null hypothesis.

χ² = Σ (O − E)² / E

Hypotheses

H₀:

The data are consistent with the proposed distribution.

H₁:

The data are not consistent with the proposed distribution.

Degrees of Freedom

The number of degrees of freedom depends on the number of categories and the number of parameters estimated from the data.

Degrees of freedom = number of categories − 1 − number of estimated parameters

Expected Frequencies

Expected frequencies should generally be sufficiently large for the chi-squared approximation to be appropriate. Where necessary, categories may need to be combined according to the conditions of the test.

TOPIC 11 • ASSOCIATION MATRIX

Contingency Tables

Contingency tables are used to investigate whether two categorical variables are associated.

Observed Frequencies

The observed frequencies are arranged in rows and columns according to the two categorical variables.

Expected Frequency

Expected frequency = (row total × column total) / grand total

Chi-Squared Statistic

χ² = Σ (O − E)² / E

Degrees of Freedom

df = (number of rows − 1)(number of columns − 1)

Hypotheses

H₀:

The two categorical variables are independent.

H₁:

The two categorical variables are associated.

Conclusion

The final conclusion should be written in context and should refer to the evidence for or against independence.

INFERENCE SIMULATION • PRACTICE

S3 Mixed Practice

These questions combine different S3 ideas rather than separating practice by chapter.

1. A population contains 480 students. A stratified sample of 60 students is required. If 180 students belong to one stratum, how many students should be selected from that stratum?
Show answer

Proportion = 180 / 480.

Required sample = (180 / 480) × 60 = 22.5.

In practice, the allocation must be adjusted to whole students while maintaining the required total sample.

2. X ~ N(12, 3²) and Y ~ N(8, 2²), independently. Find the distribution of 2X + 3Y.
Show answer

Mean = 2(12) + 3(8) = 48.

Variance = 2²(3²) + 3²(2²) = 36 + 36 = 72.

Therefore:

2X + 3Y ~ N(48, 72).

3. A population has standard deviation 12. A random sample of 36 observations is taken. Find the standard error of the sample mean.
Show answer

SE(X̄) = σ / √n

= 12 / √36 = 2.

4. Explain what it means for an estimator to be unbiased.
Show answer

An estimator is unbiased if its expected value is equal to the population parameter that it estimates.

5. State the formula for the variance of the sample mean when the population variance is σ².
Show answer

Var(X̄) = σ² / n.

6. A sample has mean 51, population standard deviation 10, and sample size 100. State the standardised statistic for testing μ = 50.
Show answer

Z = (51 − 50) / (10 / √100) = 1.

7. What does the Central Limit Theorem allow us to do with a sufficiently large sample from a non-Normal population?
Show answer

It allows the sampling distribution of the sample mean to be approximated by a Normal distribution.

8. State the formula for Spearman's rank correlation coefficient.
Show answer

rₛ = 1 − 6Σd² / [n(n² − 1)].

9. A chi-squared goodness-of-fit test has five categories and two parameters have been estimated from the data. Find the degrees of freedom.
Show answer

df = 5 − 1 − 2 = 2.

10. A contingency table has 4 rows and 3 columns. Find the degrees of freedom for a chi-squared test of independence.
Show answer

df = (4 − 1)(3 − 1) = 6.

11. In a contingency table, a row total is 80, a column total is 50 and the grand total is 200. Find the expected frequency for that cell.
Show answer

Expected frequency = (80 × 50) / 200 = 20.

12. Explain the difference between statistical significance and practical importance.
Show answer

Statistical significance means that the sample provides sufficient evidence against the null hypothesis at the chosen significance level. Practical importance concerns whether the size of the observed effect is meaningful in the real-world context.

INFERENCE DATABASE • QUICK REVIEW

S3 Key Ideas

aX ± bY ~ N(aμx ± bμy, a²σx² + b²σy²)
Var(X̄) = σ² / n
SE(X̄) = σ / √n
Z = (X̄ − μ) / (σ / √n)
rₛ = 1 − 6Σd² / [n(n² − 1)]
χ² = Σ(O − E)² / E
Expected frequency = (row total × column total) / grand total
df = (rows − 1)(columns − 1)
S3 exam checklist:
  • Identify the population parameter being investigated.
  • State H₀ and H₁ clearly.
  • Choose the correct one-tailed or two-tailed test.
  • Calculate the appropriate test statistic.
  • Use the correct significance level or critical value.
  • State the statistical decision.
  • Finish with a conclusion in context.