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EDEXCEL INTERNATIONAL A LEVEL PHYSICS • UNIT 4

Physics Unit 4

Further mechanics, electric and magnetic fields, nuclear and particle physics — with practical skills, worked examples and exam-focused practice.

TOPIC 01

Further Mechanics

Unit 4 extends mechanics into impulse, two-dimensional momentum and circular motion.

Impulse and Change of Momentum

Impulse is the product of force and the time for which the force acts. It is equal to the change in momentum.

Impulse = FΔt = Δp

A large force acting for a short time can therefore produce the same change in momentum as a smaller force acting for a longer time.

Conservation of Momentum in Two Dimensions

In an isolated system, the total momentum before an interaction equals the total momentum after the interaction.

Key idea

Momentum is a vector, so horizontal and vertical components must be considered separately in two-dimensional collisions.

Elastic and Inelastic Collisions

Momentum is conserved in both elastic and inelastic collisions when external resultant forces are negligible.

Kinetic Energy and Momentum

For a non-relativistic particle, kinetic energy can be expressed in terms of momentum.

Ek = p² / 2m

Angular Displacement

Angular displacement may be measured in radians or degrees.

2π radians = 360°

Angular Velocity

Angular velocity describes the rate at which angular displacement changes.

v = ωr
ω = 2π / T

Centripetal Acceleration

An object moving in a circle at constant speed is continuously changing direction. Therefore it has an acceleration directed towards the centre of the circle.

a = v² / r = rω²

Centripetal Force

The resultant force directed towards the centre of the circular path is called the centripetal force.

F = mv² / r = mrω²
Important

Centripetal force is not a new type of force. It is the name given to the resultant force acting towards the centre of circular motion.

Worked Example

A 2.0 kg object travels in a horizontal circle of radius 0.50 m at a speed of 4.0 m s⁻¹. Find the centripetal force.

F = mv² / r

F = (2.0 × 4.0²) / 0.50

F = 64 N

TOPIC 02

Electric & Magnetic Fields

Electric and magnetic fields describe interactions between charged particles, conductors and electromagnetic systems.

Electric Field

An electric field is a region in which a charged particle experiences a force.

Electric Field Strength

E = F / Q

Electric field strength is measured in N C⁻¹.

Force Between Two Point Charges

Coulomb's law describes the force between two point charges.

F = Q₁Q₂ / (4πε₀r²)

The force is attractive for opposite charges and repulsive for charges of the same sign.

Electric Field of a Point Charge

E = Q / (4πε₀r²)

Electric Potential

Electric potential is the work done per unit charge in bringing a positive test charge from infinity to a point.

Electric field strength is related to the rate of change of electric potential with distance.

E = ΔV / d

For a radial electric field:

V = Q / (4πε₀r)

Electric Field Lines and Equipotentials

Capacitance

Capacitance is the charge stored per unit potential difference.

C = Q / V

Energy Stored in a Capacitor

W = ½QV
W = ½CV²
W = Q² / 2C

Charging and Discharging Capacitors

A resistor-capacitor circuit has a time constant given by:

τ = RC

During discharge, charge, current and potential difference decrease exponentially.

Q = Q₀e−t/RC
I = I₀e−t/RC
V = V₀e−t/RC

Magnetic Flux Density

Magnetic flux density describes the strength of a magnetic field.

Magnetic Flux

Magnetic flux is represented by φ, while flux linkage is represented by Nφ.

Force on a Moving Charge

F = BQv sin θ

The direction of the force can be determined using Fleming's left-hand rule.

Force on a Current-Carrying Conductor

F = BIl sin θ

Electromagnetic Induction

An electromotive force can be induced when there is a change in magnetic flux linkage.

Faraday's law and Lenz's law give:

E = −N dφ/dt

The negative sign represents Lenz's law: the induced effect opposes the change that produced it.

TOPIC 03

Nuclear & Particle Physics

This section explores atomic structure, particle accelerators, particle detectors and the Standard Model's quark-lepton classification.

Nucleon Number and Proton Number

The proton number is the number of protons in a nucleus. The nucleon number is the total number of protons and neutrons.

Nucleon number = protons + neutrons

Alpha Scattering and the Nuclear Model

Large-angle alpha-particle scattering provided evidence that atoms contain a small, dense, positively charged nucleus.

Most alpha particles pass through the atom with little deflection, while a small number are strongly deflected. This demonstrates that most of the atom is empty space.

Thermionic Emission

Thermionic emission is the release of electrons from a heated material.

Electric and magnetic fields can then be used to accelerate and control the motion of these electrons.

Particle Accelerators

Particle accelerators use electric fields to increase the energy of charged particles and magnetic fields to control their paths.

Linear Accelerators

In a linear accelerator, particles are accelerated through a series of electric fields along a straight path.

Cyclotrons

A cyclotron uses alternating electric fields for acceleration and magnetic fields to bend the path of charged particles.

Charged Particles in Magnetic Fields

A charged particle moving perpendicular to a magnetic field experiences a force that can produce circular motion.

p = BQr

Therefore:

r = p / BQ

Particle Detectors

Particle detectors provide evidence about the properties and interactions of high-energy particles.

Ionisation and deflection in magnetic fields can be used to identify and study charged particles.

Conservation Laws

Particle interactions must obey conservation laws.

Mass-Energy Equivalence

Matter and antimatter can be created or annihilated when the relevant conservation laws are satisfied.

ΔE = Δmc²

Particle Energy and Mass Units

Particle physics commonly uses MeV and GeV for energy and MeV/c² and GeV/c² for mass.

Relativistic Particle Lifetime

Fast-moving unstable particles can have significantly longer observed lifetimes than when measured in their rest frame. This is a consequence of time dilation.

The Standard Quark-Lepton Model

The Standard Model classifies particles into several groups.

Quarks

The six quarks are:

Baryons

Baryons are made from three quarks. Protons and neutrons are examples.

Mesons

Mesons are made from a quark and an antiquark. Pions are examples of mesons.

Leptons

Leptons are fundamental particles. Examples include electrons and neutrinos.

Photons

Photons are fundamental particles associated with the electromagnetic interaction.

Antiparticles

Every particle has a corresponding antiparticle. The antiparticle has the same mass as its particle but opposite values for relevant conserved charges.

Particle Equations

Particle equations can be tested by applying conservation laws to both sides of an interaction.

Exam technique

When checking whether an interaction is possible, systematically compare charge, baryon number and lepton number before and after the interaction.

PRACTICAL SKILLS

Unit 4 Practical Work

Practical knowledge is important because Unit 4 examination questions can assess understanding developed through practical activities.

Core Practical 9

Investigate the relationship between the force exerted on an object and its change of momentum.

Core Practical 10

Use ICT to analyse collisions between small spheres, such as ball bearings on a table.

Core Practical 11

Use an oscilloscope or data logger to display and analyse the potential difference across a capacitor as it charges and discharges through a resistor.

Practical focus

Be prepared to discuss variables, apparatus, measurements, graphs, uncertainties, sources of error and improvements to experimental methods.

PRACTICE

Unit 4 Mixed Practice

1. A 0.50 kg ball changes velocity from 8.0 m s⁻¹ east to 4.0 m s⁻¹ west in 0.20 s. Calculate the magnitude of the average force acting on the ball.
Show answer

Take east as positive.

Δp = m(v − u)

Δp = 0.50(−4.0 − 8.0) = −6.0 kg m s⁻¹

F = Δp / Δt = −6.0 / 0.20

Magnitude = 30 N

2. A 1200 kg car travels around a circular track of radius 50 m at 10 m s⁻¹. Calculate the centripetal force.
Show answer

F = mv² / r

F = (1200 × 10²) / 50

F = 2400 N

3. A point charge produces an electric field of 2.0 × 10⁴ N C⁻¹ at a distance of 0.30 m. State the equation that relates electric field strength to point charge.
Show answer

E = Q / (4πε₀r²)

4. A capacitor has capacitance 220 μF and is charged to 12 V. Calculate the energy stored.
Show answer

W = ½CV²

W = ½ × 220 × 10⁻⁶ × 12²

W = 0.0158 J

5. A charged particle enters a magnetic field perpendicular to the field. State the equation for the magnetic force.
Show answer

F = BQv sin θ

Since θ = 90°, sin θ = 1:

F = BQv

6. Explain why a charged particle moving perpendicular to a uniform magnetic field can follow a circular path.
Show answer

The magnetic force acts perpendicular to the particle's velocity and therefore changes the direction of its velocity without changing its speed. The force acts towards the centre of the circular path and provides the centripetal force.

7. Explain why large-angle alpha scattering provided evidence for a small, dense nucleus.
Show answer

Most alpha particles passed through the atom with little deflection, showing that most of the atom is empty space. A small fraction were strongly deflected, showing that positive charge and most of the mass are concentrated in a small region: the nucleus.

8. State the quark composition of a proton and a neutron.
Show answer

Proton = uud

Neutron = udd

9. Explain how conservation laws can be used to determine whether a particle interaction is possible.
Show answer

The relevant quantities must have the same total value before and after the interaction. These include charge, energy, momentum, baryon number and lepton number. If a required conservation law is violated, the proposed interaction is not possible.

10. A particle has momentum 3.0 × 10⁻²⁰ kg m s⁻¹ and enters a magnetic field of 0.50 T. Its charge magnitude is 1.60 × 10⁻¹⁹ C. Calculate the radius of its path.
Show answer

p = BQr

r = p / BQ

r = (3.0 × 10⁻²⁰) / (0.50 × 1.60 × 10⁻¹⁹)

r = 0.375 m

QUICK REVIEW

Unit 4 Key Equations

Impulse = FΔt = Δp
Ek = p² / 2m
v = ωr
a = v² / r = rω²
F = mv² / r = mrω²
E = F / Q
F = Q₁Q₂ / (4πε₀r²)
E = Q / (4πε₀r²)
C = Q / V
W = ½CV²
τ = RC
F = BQv sin θ
F = BIl sin θ
E = −N dφ/dt
p = BQr
ΔE = Δmc²