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EDEXCEL INTERNATIONAL A LEVEL • WPH11

PHYSICS 01

Mechanics & Materials
A high-performance study environment for mastering motion, forces, momentum, energy, materials and experimental physics.

MECHANICS CORE PHYSICS
MATERIALS CORE PHYSICS
PRACTICALS EXPERIMENTAL
PRACTICE EXAM PREP
// MODULE 01

Mechanics

Understand how objects move, interact and exchange energy through the language of physics.

FOUNDATION.PROTOCOL

The Physics of Motion

Mechanics describes the motion of objects and the forces responsible for changing that motion. It forms one of the mathematical foundations of physics.

CORE CONCEPT

Motion is described using quantities such as displacement, velocity and acceleration, while forces explain how and why motion changes.

MECHANICS // 01

Scalars & Vectors

Physical quantities can be classified as scalars or vectors.

Scalars

A scalar has magnitude only.

Vectors

A vector has both magnitude and direction.

MEMORY LOCK

Distance is scalar while displacement is vector. Speed is scalar while velocity is vector.

MECHANICS // 02

Motion

Displacement

Displacement is the vector change in position of an object.

Velocity

v = Δs / Δt

Velocity is the rate of change of displacement.

Acceleration

a = Δv / Δt

Acceleration is the rate of change of velocity.

Motion Graphs

Worked Example // 001

A car increases its velocity from 8 m s⁻¹ to 20 m s⁻¹ in 4 seconds. Find its acceleration.

a = (20 − 8) / 4

a = 3 m s⁻²

MECHANICS // 03

Constant Acceleration

The SUVAT equations describe motion with constant acceleration.

v = u + at
s = ut + ½at²
v² = u² + 2as
s = ½(u + v)t
VARIABLE MATRIX

u = initial velocity • v = final velocity • a = acceleration • s = displacement • t = time

MECHANICS // 04

Forces

A force is an interaction that can change the motion or shape of an object.

Newton's Laws

Newton's First Law states that an object remains at rest or continues moving with constant velocity unless acted upon by a resultant external force.

Newton's Second Law relates resultant force to acceleration for constant mass.

F = ma
W = mg

Newton's Third Law states that interacting bodies exert equal and opposite forces on each other.

Free-Body Diagrams

A free-body diagram shows the forces acting on an object. Always identify the direction and nature of each force.

MECHANICS // 05

Moments

The moment of a force measures its turning effect about a point or axis.

Moment = Force × perpendicular distance

Equilibrium

Σ clockwise = Σ anticlockwise
Worked Example // 002

A 20 N force acts perpendicular to a beam at a distance of 0.5 m from a pivot.

Moment = 20 × 0.5

Moment = 10 N m

MECHANICS // 06

Momentum

Momentum is a vector quantity associated with the motion of an object.

p = mv
Impulse = Ft = Δp

Conservation

SYSTEM LAW

In an isolated system, total momentum remains constant.

Momentum before = Momentum after
MECHANICS // 07

Work, Energy & Power

W = Fs
Eₖ = ½mv²
Eₚ = mgh
P = W / t
CONSERVATION PROTOCOL

Energy cannot be created or destroyed. It can only be transferred between different forms.

// MODULE 02

Materials

Explore how matter responds to forces, deformation and energy storage.

MATERIALS // 01

Density

Density is the mass per unit volume of a material.

ρ = m / V

SI unit: kg m⁻³.

Worked Example // 003

A material has a mass of 0.80 kg and a volume of 2.0 × 10⁻⁴ m³.

ρ = 0.80 / (2.0 × 10⁻⁴)

ρ = 4000 kg m⁻³

MATERIALS // 02

Deformation

When a force is applied to an object, it may change its shape.

Elastic

Elastic deformation is reversible when the deforming force is removed.

Plastic

Plastic deformation produces a permanent change in shape.

ELASTIC LIMIT

Beyond the elastic limit, removing the force does not return the material completely to its original shape.

MATERIALS // 03

Hooke's Law

Within the limit of proportionality, extension is proportional to applied force.

F = kx
IMPORTANT

The limit of proportionality and elastic limit are different concepts and are not necessarily at the same point.

MATERIALS // 04

Stress, Strain & Young Modulus

Stress = F / A
Strain = ΔL / L
E = Stress / Strain

Young modulus measures the stiffness of a material.

Worked Example // 004

A wire has a cross-sectional area of 2.0 × 10⁻⁶ m² and experiences a force of 50 N.

Stress = 50 / (2.0 × 10⁻⁶)

Stress = 2.5 × 10⁷ Pa

MATERIALS // 05

Elastic Strain Energy

Work done in stretching a spring or wire can be stored as elastic strain energy.

E = ½Fx
GRAPH ANALYSIS

The area under a force-extension graph represents elastic energy stored.

// MODULE 03

Practical Physics

Experimental planning, measurement, analysis and evaluation.

01
⚡

Free Fall

Investigate motion under gravity and determine acceleration using suitable measurements or graphs.

  • Measure time and distance carefully.
  • Repeat measurements.
  • Consider reaction time.
  • Analyse suitable graphs.
02
◉

Viscosity

Investigate the motion of a sphere through a fluid and determine its behaviour at terminal velocity.

  • Allow terminal velocity.
  • Measure distance and time.
  • Control temperature.
  • Repeat measurements.
03
∆

Young Modulus

Load a wire gradually while measuring extension and determine Young modulus from experimental data.

  • Measure original length.
  • Measure diameter at several points.
  • Calculate cross-sectional area.
  • Plot appropriate graphs.
EXAM PROTOCOL

When evaluating an experiment, explain precisely what a suggested improvement changes and why it improves the quality of the measurement.

PRACTICAL // UNCERTAINTY

Measurements & Uncertainties

Experimental measurements always contain some degree of uncertainty.

Percentage Uncertainty

Percentage uncertainty = (absolute uncertainty / measured value) × 100

Reducing Uncertainty

  • Repeat measurements.
  • Calculate a mean where appropriate.
  • Use suitable-resolution instruments.
  • Increase the measured quantity where possible.
  • Control relevant variables.
SIMULATION // WORKED EXAMPLE

Mechanics Calculation

Problem

A 2.0 kg object accelerates from rest to 6.0 m s⁻¹ in 3.0 s. Calculate the resultant force.

a = (6.0 − 0) / 3.0

a = 2.0 m s⁻²

F = ma

F = 2.0 × 2.0

F = 4.0 N

// TRAINING MODE

Unit 1 Practice

Activate each solution only after attempting the question.

Q01 Explain the difference between a scalar and a vector.
REVEAL ANSWER

A scalar has magnitude only, whereas a vector has both magnitude and direction.

Q02 A car changes velocity from 12 m s⁻¹ to 30 m s⁻¹ in 6 s. Calculate its acceleration.
REVEAL ANSWER

a = (30 − 12) / 6

a = 3.0 m s⁻²

Q03 A 5.0 kg object experiences a resultant force of 20 N. Calculate its acceleration.
REVEAL ANSWER

F = ma

a = 20 / 5.0

a = 4.0 m s⁻²

Q04 A 15 N force acts 0.40 m from a pivot at right angles. Calculate the moment.
REVEAL ANSWER

Moment = 15 × 0.40

Moment = 6.0 N m

Q05 State the principle of conservation of momentum.
REVEAL ANSWER

In an isolated system, total momentum before an interaction equals total momentum after it.

Q06 A material has mass 0.60 kg and volume 3.0 × 10⁻⁴ m³. Calculate its density.
REVEAL ANSWER

ρ = m / V

ρ = 0.60 / (3.0 × 10⁻⁴)

ρ = 2.0 × 10³ kg m⁻³

Q07 State Hooke's law.
REVEAL ANSWER

Within the limit of proportionality, extension is proportional to applied force.

Q08 A wire has cross-sectional area 4.0 × 10⁻⁶ m² and experiences an 80 N force. Calculate the stress.
REVEAL ANSWER

Stress = F / A

Stress = 80 / (4.0 × 10⁻⁶)

Stress = 2.0 × 10⁷ Pa

Q09 Explain the difference between elastic and plastic deformation.
REVEAL ANSWER

Elastic deformation is reversible when the force is removed, whereas plastic deformation produces a permanent change.

Q10 Explain why repeated measurements are useful.
REVEAL ANSWER

Repeated measurements help identify random variation and allow a mean to be calculated, improving reliability.

// EQUATION DATABASE

Unit 1 Equation Matrix

Rapid-access equation reference.

v = Δs / Δt
a = Δv / Δt
v = u + at
s = ut + ½at²
v² = u² + 2as
F = ma
W = mg
p = mv
Eₖ = ½mv²
Eₚ = mgh
P = W / t
ρ = m / V
F = kx
Stress = F / A
Strain = ΔL / L
E = Stress / Strain
Elastic Energy = ½Fx
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