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EDEXCEL INTERNATIONAL A LEVEL BIOLOGY • WBI12

Biology Unit 2

Cells, Development, Biodiversity and Conservation

WBI12 Unit 2
2 Core Topics
5–9 Core Practicals
80 Marks

TOPIC 03 • CELL STRUCTURE

Cells, Microscopy and Organisation

All living organisms are made of cells. In multicellular organisms, cells become specialised and are organised into tissues, organs and organ systems.

Cell Organisation

Levels of organisation:

Cell → Tissue → Organ → Organ system → Organism

Eukaryotic Cell Ultrastructure

Eukaryotic cells contain membrane-bound organelles. The ultrastructure of these organelles can be studied using electron microscopy.

Nucleus

Contains the genetic material. The nucleolus is involved in the production of ribosomal components.

Ribosomes

Sites of protein synthesis.

Rough Endoplasmic Reticulum

Membrane network with ribosomes attached. It is involved in the synthesis and transport of proteins.

Smooth Endoplasmic Reticulum

Involved in synthesis and processing of substances including lipids.

Mitochondria

Sites of aerobic respiration and ATP production.

Golgi Apparatus

Modifies, sorts and packages proteins and other molecules for transport.

Lysosomes

Contain hydrolytic enzymes that digest materials inside cells.

Centrioles

Associated with the organisation of spindle fibres during cell division in animal cells.

Protein transport pathway:

Ribosome → rough ER → transport vesicle → Golgi apparatus → secretory vesicle → cell surface

Prokaryotic Cells

Prokaryotic cells are smaller and structurally simpler than eukaryotic cells. They do not contain a membrane-bound nucleus.

Microscopy

Microscopy allows structures that cannot be seen with the unaided eye to be observed.

Magnification = image size ÷ actual size
Actual size = image size ÷ magnification

Resolution

Resolution is the ability to distinguish two points as separate objects.

Electron microscopes generally have much greater resolving power than light microscopes.

Exam distinction:

Magnification makes an image appear larger. Resolution determines how much detail can actually be distinguished.

WORKED EXAMPLE

A cell image is 40 mm long. Its actual length is 20 μm. Calculate the magnification.

Convert 40 mm to micrometres:

40 mm = 40 000 μm

Magnification = 40 000 ÷ 20

Magnification = ×2000

Core Practical 5

Use a light microscope to make observations and labelled drawings of suitable animal cells, use a graticule to make measurements and understand scale.

TOPIC 03 • REPRODUCTION

Meiosis, Gametes, Fertilisation and the Cell Cycle

Cell division allows organisms to grow, reproduce and maintain their tissues. Meiosis produces genetically varied gametes, while mitosis produces genetically identical daughter cells.

Chromosomes and Loci

A locus is the position of a gene on a chromosome. Genes located on the same chromosome are linked.

Meiosis

Meiosis produces haploid cells from a diploid parent cell. It contributes to genetic variation through independent assortment and crossing over.

Two major sources of variation in meiosis:
  • Independent assortment of chromosomes during metaphase I.
  • Crossing over between chromatids during prophase I.

Independent Assortment

Homologous chromosome pairs line up independently of one another. This creates different combinations of maternal and paternal chromosomes in gametes.

Crossing Over

Sections of DNA can be exchanged between chromatids of homologous chromosomes. This creates new combinations of alleles.

Specialised Mammalian Gametes

Sperm Cell

Egg Cell

Mammalian Fertilisation

The sperm reaches the egg and the acrosome reaction releases enzymes. Following successful fusion, the cortical reaction helps prevent additional sperm from fertilising the egg. The nuclei eventually fuse.

Fertilisation:

Fusion of the nuclei of two haploid gametes to produce a diploid zygote.

Flowering Plant Fertilisation

A pollen grain germinates on a compatible stigma. A pollen tube grows towards the ovule and carries the male gamete nuclei towards the embryo sac, where nuclear fusion occurs.

Mitosis and the Cell Cycle

Mitosis produces genetically identical daughter cells. It is important for growth, tissue repair and asexual reproduction.

Mitotic index = number of cells undergoing mitosis ÷ total number of cells

WORKED EXAMPLE

In a root tip, 24 cells are observed. Six cells are undergoing mitosis. Calculate the mitotic index.

Mitotic index = 6 ÷ 24

Mitotic index = 0.25

As a percentage:

0.25 × 100 = 25%

Core Practical 6

Prepare and stain a root tip squash to observe the stages of mitosis and calculate mitotic indices.

Exam focus:

Be able to connect the stages of cell division with the production of genetically identical cells and with chromosome behaviour.

TOPIC 03 • DEVELOPMENT

Stem Cells, Differentiation, Gene Expression and Phenotype

Development involves cells becoming specialised. This requires different genes to be expressed in different cells.

Stem Cells

Stem cells are unspecialised cells that can divide and differentiate into specialised cell types.

Totipotent Cells

Can give rise to all cell types required to form an entire organism.

Pluripotent Cells

Can differentiate into many different cell types but are more limited than totipotent cells.

Morula and Blastocyst

After fertilisation, repeated mitotic divisions produce an early embryo. The morula develops into a blastocyst containing cells with different developmental potentials.

Cell Differentiation

Cells with the same genome can develop different structures and functions because different genes are expressed.

Differential gene expression:

Different cells activate different sets of genes, resulting in the production of different proteins and therefore different cell structures and functions.

From Gene to Protein

A gene can be transcribed to produce mRNA. The mRNA is then translated at a ribosome to produce a polypeptide.

Alternative Proteins

Post-transcriptional changes to mRNA can allow one gene to give rise to more than one protein.

Genotype and Environment

Phenotype is influenced by both genotype and environmental conditions.

Phenotype = genotype + environmental influence

Epigenetics

Epigenetic modifications can alter gene activation without changing the underlying DNA base sequence.

DNA Methylation

Methyl groups can be added to DNA and may reduce the expression of particular genes.

Histone Modification

Chemical modification of histone proteins can alter how tightly DNA is associated with histones and therefore influence gene expression.

Some epigenetic modifications can persist following cell division.

Polygenic Inheritance

Some characteristics are influenced by multiple genes. Polygenic inheritance can produce continuous variation. Environmental factors can also contribute.

EXAM THINKING

If individuals with similar genotypes show different phenotypes, consider environmental influences as well as genetic differences.

Stem Cells and Society

Stem-cell research may contribute to medical therapies, but decisions about its use involve scientific, ethical, moral and social considerations.

TOPIC 04 • PLANT STRUCTURE

Plant Cells, Tissues, Transport and Plant Products

Plant cells contain structures not found in typical animal cells and are adapted for photosynthesis, storage, support and transport.

Plant Cell Structures

Starch

Starch is a storage polysaccharide made from α-glucose. It includes amylose and amylopectin.

Cellulose

Cellulose is a structural polysaccharide made from β-glucose. Hydrogen bonding between chains contributes to the formation of strong cellulose microfibrils.

Why cellulose is strong:

Hydrogen bonds between β-glucose chains help hold cellulose molecules together, forming microfibrils that provide considerable tensile strength.

Plant Tissues

Sclerenchyma

Provides mechanical support. Thickened cell walls contribute to strength.

Xylem

Transports water and mineral ions and also contributes to support.

Phloem

Translocates organic solutes through the plant.

Comparison:
  • Sclerenchyma → support
  • Xylem → water, mineral ions and support
  • Phloem → organic solute translocation

Plant Mineral Requirements

Plants require inorganic ions for healthy growth. Important ions include nitrate, calcium and magnesium.

Nitrate Ions

Required to produce amino acids and therefore proteins.

Magnesium Ions

Required for chlorophyll production.

Calcium Ions

Important for cell walls and normal plant development.

Plant Fibres and Sustainability

Plant fibres can be used to produce materials and may contribute to sustainability by replacing some oil-based products.

Core Practical 7

Use a light microscope to observe, draw and label plan diagrams of roots, stems and leaves, and identify sclerenchyma fibres, phloem, sieve tubes and xylem vessels.

Core Practical 8

Determine the tensile strength of plant fibres.

EXAM COMPARISON

Xylem vessels have thickened walls that provide support while allowing water and mineral ions to be transported. Phloem is specialised for translocation of organic solutes.

TOPIC 04 • BIODIVERSITY

Biodiversity, Classification, Evolution and Conservation

Biodiversity describes the variety of life. It can be studied at different levels, including the variety of species and genetic variation within species.

Classification

Classification organises organisms according to similarities and differences in phenotype and genotype and is based around the species concept.

Three-Domain System

New molecular evidence can lead scientists to revise taxonomic groupings.

Biodiversity

Biodiversity refers to the variety of living organisms. Human activity has contributed to threats to biodiversity.

Endemism

An endemic species is naturally found only in a particular geographical area.

Species Richness

Species richness is the number of different species present within a particular habitat.

Heterozygosity Index

Heterozygosity index = number of heterozygotes ÷ number of individuals

Index of Diversity

The index of diversity can be used to compare biodiversity between habitats.

D = N(N − 1) ÷ Σn(n − 1)

where N is the total number of organisms and n represents the number of organisms belonging to each species.

WORKED EXAMPLE

A population contains 100 individuals, of which 20 are heterozygous for a particular gene.

Heterozygosity index = 20 ÷ 100

Heterozygosity index = 0.20

As a percentage: 20%

Niche

A niche describes the role and position of an organism within its environment.

Adaptations

Organisms may show behavioural, anatomical and physiological adaptations that increase their ability to survive and reproduce in their environment.

Hardy-Weinberg Equation

The Hardy-Weinberg equation can be used to investigate whether allele frequencies in a population are changing over time.

p + q = 1
p² + 2pq + q² = 1

Here p and q represent the frequencies of two alleles. The terms p², 2pq and q² represent genotype frequencies under the assumptions of the model.

Changes in Allele Frequency

Allele frequencies can change because of mutation and natural selection.

Speciation

Reproductive isolation can prevent gene flow between populations. Over generations, different genetic changes can accumulate and potentially result in the formation of new species.

Core evolutionary sequence:

Variation → selection pressure → differential survival and reproduction → change in allele frequency → divergence of populations

Conservation

Zoos and seed banks can help conserve endangered species and their genetic diversity.

Captive Breeding

Breeding programmes can increase population numbers and help preserve genetic diversity.

Reintroduction

Individuals can sometimes be returned to suitable natural habitats.

Seed Banks

Seeds can be stored as a means of conserving plant genetic diversity.

Education and Research

Research improves understanding of endangered species, while education can encourage conservation and reduce human pressures on habitats.

Evaluation point:

Conservation methods have benefits and limitations. For example, captive breeding can increase population size but may involve limited genetic diversity and adaptation to artificial conditions.

Core Practical 9

Investigate the antimicrobial properties of plants, including aseptic techniques for the safe handling of bacteria.

Drug Testing

Modern drug testing has developed from historical approaches to controlled scientific protocols.

CORE PRACTICALS

Unit 2 Practical Skills

Unit 2 includes practical knowledge that can be assessed through the Unit 2 examination and contributes to preparation for Unit 3 practical skills.

Core Practical 5

Light microscopy of animal cells, labelled drawings, graticule measurements and scale.

Core Practical 6

Root tip squash and observation of mitotic stages.

Core Practical 7

Microscopy of roots, stems and leaves, including identification of xylem, phloem and sclerenchyma.

Core Practical 8

Determination of tensile strength of plant fibres.

Core Practical 9

Investigation of antimicrobial properties of plants using appropriate aseptic techniques.

Recommended Additional Practical Work

PRACTICE

Unit 2 Mixed Practice

Try each question before opening the answer.

1. State two differences between prokaryotic and eukaryotic cells.
Show answer

Eukaryotic cells contain a membrane-bound nucleus and membrane-bound organelles. Prokaryotic cells do not. Prokaryotes contain circular DNA and may contain plasmids.

2. An image of a cell is 30 mm long and has a magnification of ×1500. Calculate the actual size of the cell.
Show answer

Actual size = image size ÷ magnification.

30 mm ÷ 1500 = 0.020 mm.

0.020 mm = 20 μm.

Actual size = 20 μm

3. Explain how meiosis produces genetically varied gametes.
Show answer

Independent assortment produces different combinations of chromosomes. Crossing over exchanges sections of DNA between chromatids, creating new combinations of alleles.

4. Explain why mitosis is important for growth.
Show answer

Mitosis produces genetically identical daughter cells. Increasing cell number allows tissues and organisms to grow.

5. In a sample of 200 cells, 50 are undergoing mitosis. Calculate the mitotic index.
Show answer

Mitotic index = 50 ÷ 200.

Mitotic index = 0.25

Or 25%.

6. Explain how differential gene expression causes cell specialisation.
Show answer

Different cells express different genes. This results in different mRNA molecules being produced and therefore different proteins being synthesised. The proteins influence cell structure and function.

7. Explain how cellulose provides strength to plant cell walls.
Show answer

Cellulose molecules form chains of β-glucose. Hydrogen bonds between chains help form strong cellulose microfibrils, giving the cell wall tensile strength.

8. A population contains 250 individuals and 50 are heterozygous. Calculate the heterozygosity index.
Show answer

50 ÷ 250 = 0.20.

Heterozygosity index = 0.20

9. State the three domains of classification.
Show answer

Archaea, Bacteria and Eukarya.

10. Explain how reproductive isolation can lead to speciation.
Show answer

Reproductive isolation prevents gene flow between populations. Different mutations and selection pressures can then cause genetic differences to accumulate. Eventually the populations may become sufficiently different to form separate species.

11. State the Hardy-Weinberg equations for two alleles.
Show answer

p + q = 1

p² + 2pq + q² = 1

12. Give two methods used by conservation programmes to protect endangered species.
Show answer

Examples include captive breeding, reintroduction, seed banks, scientific research and education.

QUICK REVIEW

Unit 2 Key Ideas

  • Cells are organised into tissues, organs and organ systems.
  • Eukaryotic cells contain membrane-bound organelles.
  • Prokaryotic cells contain circular DNA and lack a membrane-bound nucleus.
  • Magnification = image size ÷ actual size.
  • Resolution is the ability to distinguish two points as separate.
  • Meiosis produces genetically varied haploid gametes.
  • Independent assortment and crossing over contribute to genetic variation.
  • Mitosis produces genetically identical daughter cells.
  • Mitotic index = cells undergoing mitosis ÷ total cells.
  • Stem cells can differentiate into specialised cells.
  • Differential gene expression causes cell specialisation.
  • Phenotype is influenced by genotype and environment.
  • Epigenetic modifications can affect gene expression.
  • Cellulose microfibrils provide strength to plant cell walls.
  • Xylem transports water and mineral ions.
  • Phloem transports organic solutes.
  • Biodiversity includes variation between species and genetic diversity within species.
  • Species richness measures the number of different species in a habitat.
  • The Hardy-Weinberg equations can be used to investigate changes in allele frequency.
  • Mutation and natural selection can change allele frequencies.
  • Reproductive isolation can contribute to speciation.
  • Zoos and seed banks can contribute to conservation.